Question

(x-2 underroot6) (5 under root3+5 under root2) /5 under root 3-5 under root 2​

Answer 1

Answer:

Step-by-sStep-by-step explanation:

given that

\frac{7\sqrt{3}}{\sqrt{10}+\sqrt{3}}-\frac{2\sqrt{5}}{\sqrt{6}+\sqrt{5}}-\frac{3\sqrt{2}}{\sqrt{15}+3\sqrt{2}}\\\\=\frac{7\sqrt{3}}{\sqrt{10}+\sqrt{3}}*\frac{\sqrt{10}-\sqrt{3}}{\sqrt{10}-\sqrt{3}} -\frac{2\sqrt{5}}{\sqrt{6}+\sqrt{5}}*\frac{\sqrt{6}-\sqrt{5}}{\sqrt{6}-\sqrt{5}}-\frac{3\sqrt{2}}{\sqrt{15}+3\sqrt{2}}*\frac{\sqrt{15}-3\sqrt{2}}{\sqrt{15}-3\sqrt{2}}\\\\=\frac{7\sqrt{30}-21}{10-3}-\frac{2\sqrt{30}-10}{6-5}-\frac{3\sqrt{30}-18}{15-18}\\\\=\sqrt{30}-3-2\sqrt{30}+10+\sqrt{30}-6\\\\=1

tep explanation: