Question

(X + 2) whole cub=X(x squar-1)

Answer 1

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$<b><u>Your Question :-</u></b>$



$= > {(x + 2)}^{3} = x( {x}^{2} - 1)$



By applying the equation:-



${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3 {a}^{2} b + 3a {b}^{2}$



We get :-


$= > {x}^{3} + 8 + 6 {x}^{2} +12x = {x}^{3} -x$



$= > \cancel {x}^{3} + 8 + 6 {x}^{2} + 13x = \cancel {x}^{3}$



$\boxed{ = > 6 {x}^{2} + 13x + 8}$



$<b><i>It Is Your Required Answer </i></b>$



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