Question

x+2/x-1=1-1/x-3
answer with steps and no unnecessary answers plz​

Answer 1

Step-by-step explanation:

here we have given a series ,to find the derivative of given function, first we have to find the sum of given series

In a Geometric series is a constant, which is called the common difference n€ N

let's check the common difference of the given series,

1+(1/x)+(1/x²)+(1/x³)+....∞

here, tn=1 and tn+1=(1/x)

common difference =(tn+1)/tn =(1/x)/1 = (1/x)............(1)

for, the second one ,

tn= (1/x) ,tn+1=(1/x²)

common difference =(tn+1)/tn =(1/x²)/(1/x)=x/x²=(1/x).....(2)

from (1) and (2) given series is geometric progression.

where, a = first term and r = common difference = (1/x)

here first, we have to find the sum of series tends to infinity ,

generally sn in Gp ,

here, sum is tends to infinity so if, |r|<1 ,n is large , r^n is taken as zero so the formula will be

Now, let's find out the sum of given series [ a = 1 , r = (1/x)]

so the function becomes,

Differentiate wrt x

here use division rule for differentiation ,

if y = u/v is the function then their derivative is dy/dx=[(du/dx)v-(dv/dx)u]/v² therefore,

Now, we have ,

in the option we have x² term, so multiply denominator and numerator by x² on

Answer 2

Answer:

hello thanks for the points ......