(|x^2-x+1×+1×x+1)-(x+1×x+1)=0
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Answer:
x2+∣x−1∣=1
If x−1≥0⇒x≥1
x2+x−1=1
x2+x−2=0
(x+2)(x−1)=0
x=−2,1
x=−2, Not possible,
So, x=1 is a solution.
If x−1<0⇒x<1
x2+1−x=1
x2−x=0
x=0,1
x=0 is also a solution
x=0,1 solutions.
2 solutions.
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