Question

x^2 + (x+1)^2 = 265 find a, b, c and the discriminant​

Answer 1

Step-by-step explanation:

x²+(x+1)²=265

x²+x²+2x+1=265

2x²+2x+1=265

2x²+2x-264=0

taking 2 common

x²+x-132=0

it is in the form ax²+bx+c=0

here a=1, b=1, c=-132

discriminant is given by

∆=b²-4ac

=1²-4(1)(-132)

=1+528

∆=529