[x+2/x+1]² = x+4/ x+2 solve the linear equation
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Answer:
(x+1)^2(x+2)^2=36.
Get the square root of both sides.
(x+1)(x+2)=± 6
x^2+3x+2=± 6
x^2+3x+8 = 0 …(1)
x^2+3x-4 = 0 ..(2)
From (1), x1 and x2 = [-3±(9–32)^0.5]/2
= [-3±(-23)^0.5]/2
=[-3±√23i]/2
From (2), (x+4)(x-1) = 0
x3 = -4
x4 = 1.
So the values of x are: -4, 1, [-3±√23i]/2. Answer
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