(x+2/x+1)^2= x+4/x+3 solve it
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x^2+4+4x/x^2+1+2x=x+4/x+3
(x^2+4x+4) (x+3) =(x^2+2x+1) (x+4)
x^3+3x^2+4x^2+12x+4x+12=x^3+2x^2+x+4x^2+8x+4
x^2+4x+8=0
x=-4+√4^2-4*1*8/2 and -4-√4^2-4*1*8/2
x=0 and x= -4
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