|x^2+x+1|=3 then find the value of x
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[x×2+x+1]=3
(x2+x+1)=3
x2+x+1=-3
x=1x=union
x=-2
x-2
x=1
I hope this helps you!!
(x2+x+1)=3
x2+x+1=-3
x=1x=union
x=-2
x-2
x=1
I hope this helps you!!
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