(x^2-x+1) is a factor of the polynomial
(a) x^4+1
(b) x^4-1
(c) x^3-1
(d) x^3+1
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x³–1 is the answer because
x³– 1³ by using Identity a³-b³ = (a-b)(a²-ab+b²)
= (x – 1)[(x)² - (x)(1) + (1)²]
= (x – 1)(x²- x + 1)
Hence, x²- x + 1 is a factor of x³-1
I hope it helps you.
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