Question

(x-2)(x+1)=(x-1) (x+3)​

Answer 1

Step-by-step explanation:

transform your equation:

x²+2x+1=2x-6 ... substract 2x-6

x²+7=0

This does not have any real solutions

Have you ever heard of complex or imaginary numbers?

if yes: there are the solutions:

x= i * sqrt(7)

and

x= - i * sqrt(7)

hope it's helps you plz make me brincly

Answer 2

Answer:

x= -(1/3)

Step-by-step explanation:

(x-2) (x+1)= (x-1) (x+3)

or, x(x+1) - 2 (x+1) = x(x+3) - 1( x+3)

or, x²+ x- 2x-2 = x² + 3x- x - 3

or, x²-x -2= x² + 2x- 3

or, x²- x² -x -2x = -3 +2

or, -3x= -1

or, x = -1/ -3

∴ x= -(1/3)