(x-2) (x+1) = (x-1) (x+3)
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2
Answer:
Given:- (x-2) (x+1) = (x-1) (x+3)
x^2 + x - 2x - 2 = x^2 + 3x - 1x + 3
Now cancel x^2 from both sides
x - 2x - 2 = 3x - 1x + 3
x - 2x - 2 - 3 = 2x
Again Cancel 2x from both sides
therefore,
x - 5 = 0
x = 5
hence,
The value of x is 5 .
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Answered by
0
Answer:
3×(-5)
2+5-8÷(1)-5×21-{4}×power 5
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