Question

(x-2)(x+1)=(x-1)(x+3)
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Answer 1

$\huge \underline \bold \pink{Solution : }$

$(x - 2)(x + 1) = (x - 1)(x + 3) \\ \\ = > {x}^{2} + x - 2x - 2 = {x}^{2} + 3x - x - 3 \\ \\ = > - x - 2 = 2x - 3 \\ \\ = > 2x + x = 3 - 2 \\ \\ = > 3x = 1 \\ \\ = > x = \frac{1}{3}$

Answer 2

Answer:

Given equation (x−2)(x+1)=(x−1)(x+3)

To find whether the given equation is a quadratic equation or not

Sol:

(x−2)(x+1)=(x−1)(x+3)

⟹x ² +x−2x−2=x² +3x−x−3

⟹x²−x²+x−2x−3x+x−2+3=0

⟹−3x+1=0

This is not a quadratic equation as an equation of degree two is called a quadratic equation.

And, a polynomial when equated to zero or some value becomes an equation.