Question

(x-2) (x+1) =(x-1) (x+3) ​

Answer 1

It can be written as

x(x+1)(x+2)(x+3)(x+4) - x(x+1)(x+2)(x+3) = 0

Taking ‘ x(x+1)(x+2)(x+3) ’ common, we get

x(x+1)(x+2)(x+3){(x+4)-1} = 0

==> x(x+1)(x+2)(x+3)(x+3) = 0

==> x(x+1)(x+2)(x+3)2 = 0

So, Either x=0 or x+1 = 0 or x+2 = 0 or x+3 =0

==> x=0 or x = -1 or x = -2 or x = -3

So, the equation has roots = 0, -1, -2, -3, -3

Hope its help you

Answer 2

ANSWER:-✔✔⤵️⤵️

(X-2)(X+1)=(X-1)(X+3)

X(X+1)-2(X+1)=X(X+3)-1(X+3)

X^2+X-2X-2=X^2+3X-X-3

-X-2=X-3

-2X=-3+2

-2X=-1

X=-1/-2

X=1/2

HOPE IT HELPS YOU✨✨✌✌