Question

(x - 2) (x + 1) = (x-1)(X+ 3)
$(x - 2)(x + 1) = (x + 1)(x + 3$
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Answer 1

Answer:

x = ND  or 1

if we see the first question

(x - 2) (x + 1) = (x-1)(X+ 3)

then, 2x-3 = x-2 => x = 1

but if we see $(x+1)(x-2) = (x+1)(x+3)$

we get x+3 = x-2 => 0 = 5 that is not correct hence the value of x for that situation will not be defined