Question

x(2^x-1)(x^2+1)/(x-1)^2>0 solve using wavy curve method (don't spam or else i will I will report )

Answer 1

Answer:

$\frac{x\left(2^x-1\right)\left(x^2+1\right)}{\left(x-1\right)^2}>0\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x<0\quad \mathrm{or}\quad \:0<x<1\quad \mathrm{or}\quad \:x>1\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:0\right)\cup \left(0,\:1\right)\cup \left(1,\:\infty \:\right)\end{bmatrix}$

Step-by-step explanation:

$\frac{x\left(2^x-1\right)\left(x^2+1\right)}{\left(x-1\right)^2}>0$

$x<0\quad \mathrm{or}\quad \:0<x<1\quad \mathrm{or}\quad \:x>1$