x^2 - (x+1)×(x+2)/5x+1=6 find x
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Step-by-step explanation:
opening the bracket;
x²-x (x+2) + 1(x+2) / 5x+1=6
x² - x² -2x + x +2/5x+1=6
(x² - x² =0)
-x +2/5x+1=6
LCM is 5x
-5x + 10 /5x +1=6
By cross Multiply;
-5x +10 = 6(5x+1)
-5x + 10 = 30x +6
-5x -30x = 6 - 10
-35x = -4
so x = 35/4....
Hope it helps....
Thanks....
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