Question

x'2-x/10-21/10 factorise

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Answer 1

Answer:

$\frac{1}{10}(2x-3)(5x+7)$

Step-by-step explanation:

$x^2-\frac{x}{10}-\frac{21}{10}\\\\= \frac{10x^2-x-21}{10}\\\\=\frac{1}{10}[10x^2+14x-15x-21]\\\\=\frac{1}{10}[2x(5x+7)-3(5x+7)]\\\\=\frac{1}{10}(2x-3)(5x+7)$

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