x^2+x-2=0
pls help with he answer
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Answered by
1
Answer:
x^2+x-2=0
x^2+x=2
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Answered by
1
Given, x
2
+x−2=0⇒x
2
−(2−x)=0
So as the solution is the intersection of y=x
2
and y=2−x
They intersect at x=−2,x=1
So solution are −2,1
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