x^2+x-2=0 solve the equation in second degree equation
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Answer:
x²+x-2 = 0
x²-x+2x-2 = 0
x(x-1)+2(x-1) = 0
(x-1)(x+2) = 0
Either
x-1 = 0
x = 1
Or
x+2 = 0
x = -2
x = 1, -2
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