Question

√x^2+√x^2+1
Differenciat with respect to x

Answer 1

$\huge\boxed {ANSWER}$

SOLUTION:

• $\frac{d}{dx}( { \sqrt{x} }^{2} + \sqrt{ {x}^{2} + 1 } ) \\ = > \frac{d}{dx}(x) + \frac{d}{dx} \sqrt{ {x}^{2} + 1 } \\ = > 1 + \frac{x}{ \sqrt{ {x}^{2} + 1} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

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