(x+)² (x+2)² (x+3)² and (x + 1)³ (x-2)³ (x + 3)³
find
HCF =
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Answer:
(x+1)²(x +3)²
Step-by-step explanation:
Prime factors of (x+1)² (x+2)² (x +3)² is
(x+1)(x+1)(x+2)(x+2)(x +3)(x+3)
Prime factors of (x + 1)³ (x-2)³ (x + 3)³
(x + 1)(x + 1)(x + 1)(x-2)(x-2)(x-2)(x + 3)(x + 3)(x + 3)
So we can easily see tgw hcf (highest common factor) is
(x+1)(x+1)(x +3)(x+3)
(x+1)²(x +3)²
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