Question

x^2 - x - 2


factories and tell 2 zeroes


I will mark the brainlist​

Answer 1

Step-by-step explanation:

We Have :-

$x^{2} -x - 10$

To Find :-

$2 \: zeroes$

Method Used :-

$middle \: term \: splitting$

Solution :-

$x^{2} - x - 2 \\ \\ \\ x^{2} + x - 2x - 2 \\ \\ \\ x(x + 1) -2 (x + 1) \\ \\ \\ (x + 1)(x - 2) \\ \\ \\ to \: find \: zeroes \\ \\ \\ (x + 1)(x - 2) = 0 \\ \\ \\ for \: this \: (x + 1) \: or \: (x - 2) \: should \: be \: equal \: to \: 0 \\ \\ \\ (x + 1) = 0 \\ \\ \\ x = - 1 \\ \\ \\ when \\ \\ \\ x - 2 = 0 \\ \\ \\ x = 2 \\ \\ \\ so \: 2 \: zeroes \: are \: - 1 \: and \: 2$

Answer 2

Step-by-step explanation:

Given -

p(x) = x² - x - 2

To Find :-

Zeroes of the polynomial

Method 1 :-

In x² - x - 2,

here,

a = 1

b = -1

c = -2

Now,

Using Quadratic formula :-

• x = -b ± √b² - 4ac/2a

» -(-1) ± √(-1)² - 4×1×-2/2(1)

» 1 ± √1 + 8/2

» 1 ± √9/2

» 1 ± 3/2

Zeroes are -

• x = 1 + 3/2 = 4/2 = 2

and

• x = 1 - 3/2 = -2/2 = -1

Method 2 :-

By Middle term splitt -

x² - x - 2

» x² + x - 2x - 2

» x(x + 1) - 2(x + 1)

» (x - 2)(x + 1)

Zeroes are -

x - 2 = 0 and x + 1 = 0

• x = 2 and x = -1

Formula Used :-

Quadratic formula -

• x = -b ± √b² - 4ac/2a