Question

|x + 2| + |x -2| if x² <2
Make The following expression free from modulas sign (x belogs to R)​.
I need Solution please help.​

Answer 1

Step-by-step explanation:

$|x + 2| + |x - 2| = 0 \\ = > x + 2 + x + 2 = 0 \\ = > 2x = - 4 \\ = > x = \frac{ - 4}{2} \\ = > x = - 2$

x = -2 where x∈ R and x² = (-2)²=4 >2

No number exists with this |x + 2| + |x -2| modulus condition but if u take x = 1 then 1∈R and 1²<2