x-2-(x-2)whole square +ax-2a
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Answered by
185
Hi ,
x - 2 - ( x - 2 )² + ax - 2a
= ( x - 2 ) - ( x - 2 )² + a ( x - 2 )
= ( x - 2 ) [ 1 - ( x - 2 ) + a ]
= ( x - 2 ) [ 1 - x + 2 + a ]
= ( x - 2 ) ( 3 + a - x )
I hope this helps you.
:)
x - 2 - ( x - 2 )² + ax - 2a
= ( x - 2 ) - ( x - 2 )² + a ( x - 2 )
= ( x - 2 ) [ 1 - ( x - 2 ) + a ]
= ( x - 2 ) [ 1 - x + 2 + a ]
= ( x - 2 ) ( 3 + a - x )
I hope this helps you.
:)
Answered by
29
Answer:
hope this help you
Step-by-step explanation:
ok...............
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