Question

(x-2)(x+2)(x^2+4)(x^4+16)​

Answer 1

Answer

$(x-2)(x+2)(x²+4)(x⁴+16)=(x²-4)(x⁴+4)(x⁴+16)$

$=[(x²)²-(4)²](x⁴+16)$

$=(x⁴-16)(x⁴+16)$

$=(x⁴)²-(16)²$

$=x⁸-256$

Answer 2

Answer:

Answer

(x-2)(x+2)(x²+4)(x⁴+16)=(x²-4)(x⁴+4)(x⁴+16)(x−2)(x+2)(x²+4)(x⁴+16)=(x²−4)(x⁴+4)(x⁴+16)

=[(x²)²-(4)²](x⁴+16)=[(x²)²−(4)²](x⁴+16)

=(x⁴-16)(x⁴+16)=(x⁴−16)(x⁴+16)

=(x⁴)²-(16)²=(x⁴)²−(16)²

=x⁸-256=x⁸−256