Question

(x^2+x-2) (x^2-x-6) x^2-4x+3) is a perfect square

Answer 1

Answer:

Yes

Step-by-step explanation:

Factorizing the individual quadratics:

• x² + x - 2  =  (x - 1)(x + 2)
• x² - x - 6  =  (x - 3)(x + 2)
• x² - 4x + 3 = (x - 1)(x - 3)

So their product is:

• (x² + x - 2)(x² - x - 6)(x² - 4x + 3)  =  [(x - 1)(x - 3)(x + 2)]²

which is a perfect square!