Math, asked by rahulkumar1446, 8 months ago

x^2-(x+2)(x+3)/7x+1=2/3​

Answers

Answered by pukultanvi4444
2

Answer:

x=0.439035

Step-by-step explanation:

Let's solve your equation step-by-step.

x2−

(x+2)(x+3)/7x+1=2/3

−1/7x3+2/7x2+−6/7x+1=2/3

Step 1: Subtract 2/3 from both sides.

−1/7x3+2/7x2+−6/7x+1−2/3=2/3−2/3

−1/7x3+2/7x2+−6/7x+1/3=0

Step 2: Use cubic formula.

x=0.439035

Answered by shashiawasthi069
1

Step-by-step explanation:

x^2-(x+2)(x+3)/7x+1=2/3

(x^2-x^2-3x-2x+6)/7x+1 = 2/3

3(x^2-x^2-3x-2x+6) = 2(7x+1)

3(-5x+6) = 2(7x+1)

-15x-18 = 14x+2

-15x-14x = 2+18

-29x = 20

x = -20/29

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