x^2-(x+2)(x+3)/7x+1=2/3
Answers
Answered by
2
Answer:
x=0.439035
Step-by-step explanation:
Let's solve your equation step-by-step.
x2−
(x+2)(x+3)/7x+1=2/3
−1/7x3+2/7x2+−6/7x+1=2/3
Step 1: Subtract 2/3 from both sides.
−1/7x3+2/7x2+−6/7x+1−2/3=2/3−2/3
−1/7x3+2/7x2+−6/7x+1/3=0
Step 2: Use cubic formula.
x=0.439035
Answered by
1
Step-by-step explanation:
x^2-(x+2)(x+3)/7x+1=2/3
(x^2-x^2-3x-2x+6)/7x+1 = 2/3
3(x^2-x^2-3x-2x+6) = 2(7x+1)
3(-5x+6) = 2(7x+1)
-15x-18 = 14x+2
-15x-14x = 2+18
-29x = 20
x = -20/29
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