Question

x^2 = (x^2+y^2-2xy) ^2 find x write in steps ! please!

Answer 1

Answer:

Step-by-step explanation:

$x^{2} =(x^{2} + y^{2} - 2xy)^{2}$   ...................     Taking square root on both sides

$x= x^{2} +y^{2} - 2xy\\x - x^{2} =y^{2} -2xy\\x(1-x) = y(y-2x)\\x= \frac{ y(y-2x)\\}{1-x}$