Question

x^2+x-20=0 solve by factorization ​

Answer 1

$\mathtt{: {x}^{2} + x - 20 = 0}$

$\mathtt{: \implies {x}^{2} + 5x - 4x - 20 = 0}$

$\mathtt{: \implies \: x(x + 5) - 4(x + 5) = 0}$

$\color{green}{\mathtt{ \implies(x - 4)(x + 5) = 0}}$

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Values of x are 4 & -5 .

=》 x - 4 = 0

= x = 4

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=》 x + 5 = 0

= 0= x = -5