Question

x^2 + x-20


please solve​

Answer 1

Answer:

x=-5 or x=4

Step-by-step explanation:

${x}^{2} + x - 20 = 0 \\ {x}^{2} + 5x - 4x - 20 = 0 ...(( + 5 - 4 = 1)( + 5 \times - 4 = - 20)) \\ x(x + 5) - 4(x + 5) = 0 \\ (x + 5)(x - 4) = 0 \\ x + 5 = 0 \: or \: x - 4 = 0 \\ x = - 5 \: or \: x = 4$