Math, asked by Whatismynamedont, 8 months ago

X^2 + x - 2550 = 0 I will mark you brainliest

Answers

Answered by laxmikumawat10071982

Answer:

The last term, "the constant", is -2550

Step-1 : Multiply the coefficient of the first term by the constant 1 • -2550 = -2550

Step-2 : Find two factors of -2550 whose sum equals the coefficient of the middle term, which is 1 .

-2550 + 1 = -2549

-1275 + 2 = -1273

-850 + 3 = -847

-510 + 5 = -505

-425 + 6 = -419

-255 + 10 = -245

-170 + 15 = -155

-150 + 17 = -133

-102 + 25 = -77

-85 + 30 = -55

-75 + 34 = -41

-51 + 50 = -1

-50 + 51 = 1 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -50 and 51

x2 - 50x + 51x - 2550

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-50)

Add up the last 2 terms, pulling out common factors :

51 • (x-50)

Step-5 : Add up the four terms of step 4 :

(x+51) • (x-50)

Which is the desired factorization

Equation at the end of step

(x + 51) • (x - 50) = 0

STEP

Theory - Roots of a product

2.1 A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation:

2.2 Solve : x+51 = 0

Subtract 51 from both sides of the equation :

x = -51

Solving a Single Variable Equation:

2.3 Solve : x-50 = 0

Add 50 to both sides of the equation :

x = 50

Supplement : Solving Quadratic Equation Directly

Solving x2+x-2550 = 0 directly

Earlier we factored this polynomial by splitting the middle term. let us now solve the equation by Completing The Square and by using the Quadratic Formula

Parabola, Finding the Vertex:

3.1 Find the Vertex of y = x2+x-2550

Parabolas have a highest or a lowest point called the Vertex . Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) . We know this even before plotting "y" because the coefficient of the first term, 1 , is positive (greater than zero).

Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.

Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.

For any parabola,Ax2+Bx+C,the x -coordinate of the vertex is given by -B/(2A) . In our case the x coordinate is -0.5000

Plugging into the parabola formula -0.5000 for x we can calculate the y -coordinate :

y = 1.0 * -0.50 * -0.50 + 1.0 * -0.50 - 2550.0

or y = -2550.250

Parabola, Graphing Vertex and X-Intercepts :

Root plot for : y = x2+x-2550

Axis of Symmetry (dashed) {x}={-0.50}

Vertex at {x,y} = {-0.50,-2550.25}

x -Intercepts (Roots) :

Root 1 at {x,y} = {-51.00, 0.00}

Root 2 at {x,y} = {50.00, 0.00}

Answered by khushi8557