Question

(x+2)(x+3)=0 ax square+bx+c=0 write the values of a,b,c

Answer 1

Answer:

The answer is $a=1,b=5,c=6$

Step-by-step explanation:

Given equation is

              $(x+2)(x+3)=0$

           $\Rightarrow x(x+3)+2(x+3)=0\\\Rightarrow x^2+3x+2x+6=0\\\Rightarrow x^2+5x+6=0$

Now comparing it with $ax^2+bx+c=0$, we have

             $a=1,b=5,c=6$