(x−2)(x+3)=0,Examine whether the given equation are quadratic equations or not.
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(x-2)(x+3)=x^2+3x-2x+6=0
=x^2+x+6=0
as it's degree is 2,
therefore (x-2)(x-3) is a quadratic equation.
=x^2+x+6=0
as it's degree is 2,
therefore (x-2)(x-3) is a quadratic equation.
Answered by
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hey user!!!
given :- ( x - 2 ) ( x + 3 ) = 0
>> x ( x + 3 ) - 2 ( x + 3 ) = 0
>> x² + 3x - 2x + 3 = 0
>> x² + x + 3 = 0
we can clearly see here that x² + x + 3 is a quadratic polynomial. hence, the given equation is quadratic equation.
cheers!!!
given :- ( x - 2 ) ( x + 3 ) = 0
>> x ( x + 3 ) - 2 ( x + 3 ) = 0
>> x² + 3x - 2x + 3 = 0
>> x² + x + 3 = 0
we can clearly see here that x² + x + 3 is a quadratic polynomial. hence, the given equation is quadratic equation.
cheers!!!
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