Question

x^2-x-3=0
plz solve this q​

Answer 1

We will be using the quadratic formula here...

Given: x^2-x-3=0

where. a=1,b=-1,c=3

d=b^2-4ac

so, d=(-1^2)-4(1)(3)

d=1+12

=13

As we know,

x=(-b+rootd)/2a. Or. (-b-rootd)/2a

x=(1+root13)/2 ; x=(1-root13)/2

Hope this is the needful...