Question

(x+2) (x+3)=0
solve from quadric equation​

Answer 1

Step-by-step explanation:

hope it helps

~~~~~~..~....

Answer 2

Answer:

$x^{2}$+5x+6=0

Step-by-step explanation:-

(x+2)(x+3)=0

x(x+3)+2(x+3)=0

$x^{2}$+3x+2x+6=0

$x^{2}$+5x+6=0