Question

(x-2)(x+3)=x+1÷a² quadratic

Answer 1

Answer:

(x-2)(x-3)=x+1/a²

x²-3x-2x+6=x+1/a²

x²-6x-1/a²=0

root formula: [-b±√(b²-4ac)]/2a

x=[6±√(36+4/a²)]/2

x=6/2±2√(9+1/a²)/2

x=3±√(9+1/a²)

hence x=3+√(9+2/a²)

x=3-√(9+1/a²)