Math, asked by falconbaaz07, 9 months ago

(x+2) (x+3)-(x+2) (x-3)=0.find the value of x. pls its urgent

Answers

Answered by studenta62
0

Answer:

the answer is ---

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I've clearly done the sum step by step

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Answered by Anonymous
20

Answer:

( x + 2)(x + 3) - (x + 2)(x - 3) = 0 \\  \\  \\  =  > (x + 2)((x + 3) - (x - 3))  = 0\\  \\  =  > (x + 2)(x + 3 - x + 3)  = 0\\  \\  =  > (x + 2)(6) = 0 \\  \\  \\  =  > 6x + 12 = 0  \\  \\  =  > 6x =  - 12 \\  \\  \\ x =  \frac{ - 12}{6}  \\  \\  = x =  - 2

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