(x+2)(x+3)-(x+2)(x-3)=0
find x=?
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(x + 2)(x + 3) - (x + 2)(x - 3) = 0
Taking (x + 2) common, we gets,
(x + 2) { (x + 3) - (x - 3) } = 0
=> (x + 2) { x + 3 - x + 3 } = 0
=> (x + 2) (6) = 0
=> x + 2 = 0
=> x = -2
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