Math, asked by mayankroshanshetty, 11 months ago

(x+2) (x+3)+ (x-2) (x-3) - 2x (x+1) = 0

Answers

Answered by AnandRaj6277
1

Step-by-step explanation:

(x+2)(x+3)+(x-2)(x-3)-2x(x+1)=0

x(x+3)+2(x+3)+x(x-3)-2(x-3)-2x²-2x=0

x²+3x+2x+6+x²-3x-2x+6-2x²-2x=0

x²+x²-2x²+3x+2x-3x-2x-2x+6+6=0

12-2x=0

2x=12

x=12/2

x=6

Answered by warisaraihanw
0

Answer:

1/6

Step-by-step explanation:

(x+2)(x+3)+(x-2)(x-3)-2x(x+1)=0

x²+5x+6+x²-5x+6-2x²-2x=0

12-2x=0

2(6x-1)=0

x=1/6

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