Question

(x+2/x-3)(x-2/x-3) Expand

Answer 1

Since

(x-3)is common on both the sides so we are taking them in the first term and then 2/x

so it stands like this----

(x-3+2/x)(x-3-2/x)

Let x-3 be 'a'

(a+2/x)(a-2/x)

a^2 -(2/x)^2

a^2 -4/x^2

so substitute the value of a in (x-2)

(x-3)^2 -4/x^2

x^2 +3^2 -2 (x)(3)-4/x^2

x^2 + 9 -6x -4/x^2

Hope it helps thou a lot ❤