Question

(x + 2)(x + 3) + (x - 3)(x - 2) - 2x (x + 1) = 0​

Answer 1

Answer:

(x+2)(×+3)+(x-3)(x-2)-2x (x+1)=0

=x^2 +3x +2x+6 +x^2 -3x -2x+6=0+2x (x+1)

=2x^2 +12=2x^2 +2x

=2x^2-2x^2 =2x-12

=0=2x-12

= 12=2x

=12÷2=x

=6=x

Answer 2

Solution:-

=>(x+2) (x+3) + (x-3) (x-2) -2x(x+1) = 0

=>(x²+3x+2x+6 )+(x²-2x-3x+6)

-2x²-2x = 0

=> x²+5x+6 + x²-5x+6 - 2x² - 2x = 0

we can write it as

=> x² + x² - 2x² + 5x - 5x - 2x + 6 + 6 = 0

=> 2x² - 2x² - 2x + 12 = 0

=> - 2x + 12 = 0

=> - 2x = - 12

=> 2x = 12

=> x = 12/2

=> x = 6

i hope it helps you.