Question

(x+2) (x+3) + (x-3) (x-2) _2x (x+1=0​

Answer 1

Step-by-step explanation:

x square +3x +2x+ 6 +x square-2x -3x-6 -2x square +2x =0

2x square +5x +6 -5x -6 -2x square+2x =0

2x=0

therefore

x=0/2 .

Answer 2

Solution:-

=>(x+2) (x+3) + (x-3) (x-2) -2x(x+1) = 0

=>(x²+3x+2x+6 )+(x²-2x-3x+6)

-2x²-2x = 0

=> x²+5x+6 + x²-5x+6 - 2x² - 2x = 0

we can write it as

=> x² + x² - 2x² + 5x - 5x - 2x + 6 + 6 = 0

=> 2x² - 2x² - 2x + 12 = 0

=> - 2x + 12 = 0

=> - 2x = - 12

=> 2x = 12

=> x = 12/2

=> x = 6

i hope it helps you.