Question

(x+2) (x+3) + (x-3) (x-2) -2x (x+1)=0​

Answer 1

Answer:

x=6

Step-by-step explanation:

(x+2)(x+3) = x²+5x+6...equ1

(x-3)(x-2) = x²-5x+6......equ2

-2x(x+1) = -2x²-2x......equ3

adding 3 equ

x²+5x+6+x²-5x+6-2x²-2x

gives

12-2x

x = 6.

Answer 2

Solution:-

=>(x+2) (x+3) + (x-3) (x-2) -2x(x+1) = 0

=>(x²+3x+2x+6 )+(x²-2x-3x+6)

-2x²-2x = 0

=> x²+5x+6 + x²-5x+6 - 2x² - 2x = 0

we can write it as

=> x²+x²-2x² +5x-5x -2x +6+6 = 0

=> 2x² - 2x² - 2x + 12 = 0

=> - 2x + 12 = 0

=> - 2x = - 12

=> 2x = 12

=> x = 12/2

=> x = 6

i hope it helps you.