Question

(x+2) (x+3) + (x-3) (x-2) -2x (x+1)=0

Answer 1

hello users .....

we have:
(x+2) (x+3) + (x-3) (x-2) -2x (x+1)=0

solution:-
(x+2) (x+3) + (x-3) (x-2) -2x (x+1)

= {x(x+3) +2(x+3)} + { x(x-2) - 3(x-2)} - { 2x² + 2x} = 0

= (x² +3x + 2x +6) + (x² -2x - 3x +6) - 2x² -2x = 0

=> x² +5x +6 + x² -5x +6 - 2x² -2x = 0

=> 12 - 2x = 0

=> 2x = 12

=> x = 6 Answer

⭐✡ hope it helps ⭐✡

Answer 2

Solution:-

=>(x+2) (x+3) + (x-3) (x-2) -2x(x+1) = 0

=>(x²+3x+2x+6 )+(x²-2x-3x+6)

-2x²-2x = 0

=> x²+5x+6 + x²-5x+6 - 2x² - 2x = 0

we can write it as

=> x² + x² - 2x² + 5x - 5x - 2x + 6 + 6 = 0

=> 2x² - 2x² - 2x + 12 = 0

=> - 2x + 12 = 0

=> - 2x = - 12

=> 2x = 12

=> x = 12/2

=> x = 6

i hope it helps you.