Question

(x + 2) (x + 3) + (x-3)(x-2)-2x(x + 1) = 0​

Answer 1

QUESTION ASKED ;

(x + 2) ( x + 3) + ( x - 3) ( x - 2) - 2x( x + 1) = 0

Method to do :

just take common and multiply the term , after doing that do the Algebraic expression law , you will find you answer,

SOLUTION :

x ( x + 3) + 2( x + 3) + x( x - 2) - 3( x - 2) - 2x( x + 1) = 0

or, x² + 3x + 2x + 6 + x² - 2x - 3x + 6 - 2x² - 2x = 0

or, 2x² - 2x² + 5x - 7x + 12 = 0

or, 12 - 2x = 0

or , 12 = 2x

or, x = 12 /2

therefore , x = 6 answer

Answer 2

Solution:-

=>(x+2) (x+3) + (x-3) (x-2) -2x(x+1) = 0

=>(x²+3x+2x+6 )+(x²-2x-3x+6)

-2x²-2x = 0

=> x²+5x+6 + x²-5x+6 - 2x² - 2x = 0

we can write it as

=> x²+x²-2x² +5x-5x -2x +6+6 = 0

=> 2x²-2x² - 2x + 12 = 0

=> - 2x + 12 = 0

=> - 2x = - 12

=> 2x = 12

=> x = 12/2

=> x = 6

i hope it helps you.