Question

(x+2) (x+3) + (x-3) (x-2)-(2x (x+1)=0​

Answer 1

Answer:

6

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$Given \: that,$

$( \times + 2) \: ( \times + 3) + ( \times - 3)( \times - 2) - 2x \: ( \times + 1) = 0$

$⇒ \times {}^{2} + 2x + 3x + 6 + x {}^{2} - 3x - 2x + 6 - 2x {}^{2} - 2x = 0$

$⇒2x {}^{2} </p><p> −2x {}^{2} </p><p> +5x−5x−2x+12=0$

$⇒ - 2 \times + 12 = 0$

$⇒ - 2 \times = - 12$

$⇒x =6$