(x + 2) (x + 3) + (x-3) (x - 2) – 2x (x + 1) = 0
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x²+3x+2x+6+x²-2x-3x+6-2x²-2x=0
-2x+12=0
x=6
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Given That ,
(x + 2) (x + 3) + (x-3) (x - 2) – 2x (x + 1) = 0
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Solution - ( In Attachment)
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