Math, asked by yatharthKashyap, 4 months ago

(x + 2)(x + 3) + (x - 3)(x - 2) - 2x (x + 1) = 0​

Answers

Answered by s525454
1

Answer:

x=6

Step-by-step explanation:

(x+2)(x+3)+(x−3)(x−2)−2x(x+1)=0

⇒x  

2

+2x+3x+6+x  

2

−3x−2x+6−2x  

2

−2x=0

⇒2x  

2

−2x  

2

+5x−5x−2x+12=0

⇒−2x+12=0

⇒−2x=−12

⇒x=6

Answered by amansharma264
5

EXPLANATION.

⇒ (x + 2)(x + 3) + (x - 3)(x - 2) - 2x(x + 1) = 0.

As we know that,

Evaluate the equation into simple form, we get.

⇒ (x² + 3x + 2x + 6) + (x² - 2x - 3x + 6) - (2x² + 2x) = 0.

⇒ (x² + 5x + 6) + (x² - 5x + 6) - (2x² + 2x) = 0.

⇒ x² + 5x + 6 + x² - 5x + 6 - 2x² - 2x = 0.

⇒ 2x² - 2x² + 5x - 5x - 2x + 6 + 6 = 0.

⇒ - 2x + 12 = 0.

⇒ 2x = 12.

⇒ x = 6.

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