Question

(x+2)(x+3)+(x-3)(x-2)-2x(x+1)=0
find the value of 'x' .
please it's urgent. ​

Answer 1

Answer:

$(x + 2)(x + 3) + (x - 3)(x - 2) - 2x(x + 1) = 0$

$= > (x ^{2} + 3x + 2x + 6) + ( {x}^{2} - 2x - 3x + 6) - 2 {x}^{2} - 2x = 0$

$= > 2 {x}^{2} + 5x + 6 - 5x + 6 - 2 {x}^{2} - 2x = 0$

$= > 12 - 2x = 0(other \: terms \: are \: cancelled \: out)$

$= > 2x = 12$

$= > x = 6(answer)$

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