(x+2) (x+3) + (x-3) (x-2) -2x (x+1) = 0
Just find value of x thanks 8th grade
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gargarya:
It's wrong ans is supposed to be 6 but idk how to do it
Ya the was one more 6 to be answered
Plzz mark me brilliant
I had got the answer as 6 at first but now when I tried it again I got it as -6
Ok you are right it is 6
i got it
Plzz mark me as brilliant
Ok
I can't cuz there shod be 2 guys
answer is 6.
Answered by
34
Solution:-
=>(x+2) (x+3) + (x-3) (x-2) -2x(x+1) = 0
=>(x²+3x+2x+6 )+(x²-2x-3x+6)
-2x²-2x = 0
=> x²+5x+6 + x²-5x+6 - 2x² - 2x = 0
we can write it as
=> x²+x²-2x² +5x-5x -2x +6+6 = 0
=> 2x²-2x² - 2x + 12 = 0
=> - 2x + 12 = 0
=> - 2x = - 12
=> 2x = 12
=> x = 12/2
=> x = 6
i hope it helps you.
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